countAndSayNORECURSION.py

# playing with append instead of using suffix[i] = prefix/suffix but I need to reverse the list which takes time
class Solution:
    def numToSay(self, num):
        i = 0
        myStr = ""
        
        while i < len(num):
            number = num[i]
            countChars = 0
            while i < len(num) and num[i] == number:
                
                countChars += 1
                i += 1
            #trick happens here
            myStr += str(countChars) + number
            
        return myStr
        
        
    def countAndSay(self, n):
        s = "1"
        for i in range(n-1):
            # s becomes the result of whatever digit(s) 
            # you are processing. in this case "num" becomes 11
            s = self.numToSay(s)
        return s
myVar = Solution()     
myVar.countAndSay(7)