给定一个整数 n
,返回所有长度为 n
的 中心对称数 。你可以以 任何顺序 返回答案。
中心对称数 是一个数字在旋转了 180
度之后看起来依旧相同的数字(或者上下颠倒地看)。
示例 1:
输入:n = 2 输出:["11","69","88","96"]
示例 2:
输入:n = 1 输出:["0","1","8"]
提示:
1 <= n <= 14
class Solution:
def findStrobogrammatic(self, n: int) -> List[str]:
def dfs(u):
if u == 0:
return ['']
if u == 1:
return ['0', '1', '8']
ans = []
for v in dfs(u - 2):
for l, r in [['1', '1'], ['8', '8'], ['6', '9'], ['9', '6']]:
ans.append(l + v + r)
if u != n:
ans.append('0' + v + '0')
return ans
return dfs(n)
class Solution {
private int n;
public List<String> findStrobogrammatic(int n) {
this.n = n;
return dfs(n);
}
private List<String> dfs(int u) {
if (u == 0) {
return Collections.singletonList("");
}
if (u == 1) {
return Arrays.asList("0", "1", "8");
}
List<String> ans = new ArrayList<>();
int[][] pairs = new int[][]{{1, 1}, {8, 8}, {6, 9}, {9, 6}};
for (String v : dfs(u - 2)) {
for (int[] p : pairs) {
ans.add(p[0] + v + p[1]);
}
if (u != n) {
ans.add("0" + v + "0");
}
}
return ans;
}
}
class Solution {
public:
int n;
vector<string> findStrobogrammatic(int n) {
this->n = n;
return dfs(n);
}
vector<string> dfs(int u) {
if (u == 0) return {""};
if (u == 1) return {"0", "1", "8"};
vector<string> ans;
vector<vector<char>> pairs = {{'1', '1'}, {'8', '8'}, {'6', '9'}, {'9', '6'}};
for (string v : dfs(u - 2))
{
for (auto& p : pairs) ans.push_back({p[0] + v + p[1]});
if (u != n) ans.push_back('0' + v + '0');
}
return ans;
}
};
func findStrobogrammatic(n int) []string {
var dfs func(int) []string
dfs = func(u int) []string {
if u == 0 {
return []string{""}
}
if u == 1 {
return []string{"0", "1", "8"}
}
var ans []string
pairs := [][]string{{"1", "1"}, {"8", "8"}, {"6", "9"}, {"9", "6"}}
for _, v := range dfs(u - 2) {
for _, p := range pairs {
ans = append(ans, p[0]+v+p[1])
}
if u != n {
ans = append(ans, "0"+v+"0")
}
}
return ans
}
return dfs(n)
}