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+ // Regression test for #57979. This situation is meant to be an error.
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+ // As noted in the issue thread, we decided to forbid nested impl
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+ // trait of this kind:
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+ //
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+ // ```rust
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+ // fn foo() -> impl Foo<impl Bar> { .. }
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+ // ```
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+ //
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+ // Basically there are two hidden variables here, let's call them `X`
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+ // and `Y`, and we must prove that:
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+ //
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+ // ```
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+ // X: Foo<Y>
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+ // Y: Bar
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+ // ```
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+ //
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+ // However, the user is only giving us the return type `X`. It's true
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+ // that in some cases, we can infer `Y` from `X`, because `X` only
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+ // implements `Foo` for one type (and indeed the compiler does
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+ // inference of this kind), but I do recall that we intended to forbid
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+ // this -- in part because such inference is fragile, and there is not
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+ // necessarily a way for the user to be more explicit should the
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+ // inference fail (so you could get stuck with no way to port your
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+ // code forward if, for example, more impls are added to an existing
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+ // type).
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+ //
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+ // The same seems to apply in this situation. Here there are three impl traits, so we have
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+ //
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+ // ```
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+ // X: IntoIterator<Item = Y>
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+ // Y: Borrow<Data<Z>>
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+ // Z: AsRef<[u8]>
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+ // ```
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+
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+ use std:: borrow:: Borrow ;
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+
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+ pub struct Data < TBody > ( TBody ) ;
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+
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+ pub fn collect ( _: impl IntoIterator < Item = impl Borrow < Data < impl AsRef < [ u8 ] > > > > ) {
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+ //~^ ERROR
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+ unimplemented ! ( )
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+ }
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