Does anyone know how to return errors from resolvers?

[special-character]

I am currently throwing errors from my resolver with a middleware but I am not sure how to make the response a 200.

ex:

schema.middleware(() => {
  return async (root, args, context, info, next) => {
    try {
      const result = await next(root, args, context, info)
      return result
    } catch (error) {
      Sentry.captureException(error)
      log.error('error', { error })
      // ensure the response has the "error" field on it
      throw error
    }
  }
})

If I don't throw the error from the middleware the error field is not on the returned data. I feel like there must be a way to get the error field without throwing the error in the resolver itself but I didn't see much in the docs yet here: https://www.nexusjs.org/#/guides/error-handling?id=global

Thanks for any help!

[Weakky]

Hey @special-character, sorry for the late response. I believe the only way to get a 200 response while returning an error is to model your error at the GraphQL schema level.

There's a great article talking about that here https://medium.com/@sachee/200-ok-error-handling-in-graphql-7ec869aec9bc

[special-character]

Thanks for the reply! This seems straightforward to me. For some reason I thought this was handled out of the box but looks like I was wrong.